Log^2(4x-7)=1

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Solution for Log^2(4x-7)=1 equation: 


Simplifying
Log2(4x + -7) = 1

Reorder the terms:
g2oL(-7 + 4x) = 1
(-7 * g2oL + 4x * g2oL) = 1
(-7g2oL + 4g2oxL) = 1

Solving
-7g2oL + 4g2oxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -7g2oL + 4g2oxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -7g2oL + 4g2oxL = 0

The solution to this equation could not be determined.

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